At 07 10, Joelle left Town B and cycled towards Town C. Opal left Town B and cycled towards Town C at 07 30. Opal's cycling speed was 3 km/h faster than Joelle. At 11 10, Opal caught up with Joelle. Find the cycling speed of each cyclist.
- Joelle
- Opal
(a)
Duration that Opal cycled from 07 30 to 11 10
= 3
4060 = 3
23 h
Distance that Opal cycled more than Joelle
= 3
23 x 3
= 11 km
However, since Joelle left 20 minutes earlier than Opal and Opal caught up with Joelle, it means that Joelle has cycled 11 km in 20 min.
1 h = 60 min
20 min = 20 ÷ 60 =
13 h
Joelle's cycling speed
= 11 ÷
13 = 11 x
31 = 33 km/h
(b)
Opal's cycling speed
= 33 + 3
= 36 km/h
Answer(s): (a) 33 km/h ; (b) 36 km/h
