At 07 25, Rachel left Town M and cycled towards Town N. Min left Town M and cycled towards Town N at 07 55. Min's cycling speed was 4 km/h faster than Rachel. At 10 25, Min caught up with Rachel. Find the cycling speed of each cyclist.
- Rachel
- Min
(a)
Duration that Min cycled from 07 55 to 10 25
= 2
3060 = 2
12 h
Distance that Min cycled more than Rachel
= 2
12 x 4
= 10 km
However, since Rachel left 30 minutes earlier than Min and Min caught up with Rachel, it means that Rachel has cycled 10 km in 30 min.
1 h = 60 min
30 min = 30 ÷ 60 =
12 h
Rachel's cycling speed
= 10 ÷
12 = 10 x
21 = 20 km/h
(b)
Min's cycling speed
= 20 + 4
= 24 km/h
Answer(s): (a) 20 km/h ; (b) 24 km/h
