At 09 25, Diana left Town A and cycled towards Town B. Winnie left Town A and cycled towards Town B at 09 55. Winnie's cycling speed was 2 km/h faster than Diana. At 11 25, Winnie caught up with Diana. Find the cycling speed of each cyclist.
- Diana
- Winnie
(a)
Duration that Winnie cycled from 09 55 to 11 25
= 1
3060 = 1
12 h
Distance that Winnie cycled more than Diana
= 1
12 x 2
= 3 km
However, since Diana left 30 minutes earlier than Winnie and Winnie caught up with Diana, it means that Diana has cycled 3 km in 30 min.
1 h = 60 min
30 min = 30 ÷ 60 =
12 h
Diana's cycling speed
= 3 ÷
12 = 3 x
21 = 6 km/h
(b)
Winnie's cycling speed
= 6 + 2
= 8 km/h
Answer(s): (a) 6 km/h ; (b) 8 km/h
