At 05 20, Julie left Town X and cycled towards Town Y. Cathy left Town X and cycled towards Town Y at 05 50. Cathy's cycling speed was 2 km/h faster than Julie. At 15 20, Cathy caught up with Julie. Find the cycling speed of each cyclist.
- Julie
- Cathy
(a)
Duration that Cathy cycled from 05 50 to 15 20
= 9
3060 = 9
12 h
Distance that Cathy cycled more than Julie
= 9
12 x 2
= 19 km
However, since Julie left 30 minutes earlier than Cathy and Cathy caught up with Julie, it means that Julie has cycled 19 km in 30 min.
1 h = 60 min
30 min = 30 ÷ 60 =
12 h
Julie's cycling speed
= 19 ÷
12 = 19 x
21 = 38 km/h
(b)
Cathy's cycling speed
= 38 + 2
= 40 km/h
Answer(s): (a) 38 km/h ; (b) 40 km/h
