At 06 20, Yoko left Town L and cycled towards Town M. Ivory left Town L and cycled towards Town M at 06 40. Ivory's cycling speed was 3 km/h faster than Yoko. At 10 20, Ivory caught up with Yoko. Find the cycling speed of each cyclist.
- Yoko
- Ivory
(a)
Duration that Ivory cycled from 06 40 to 10 20
= 3
4060 = 3
23 h
Distance that Ivory cycled more than Yoko
= 3
23 x 3
= 11 km
However, since Yoko left 20 minutes earlier than Ivory and Ivory caught up with Yoko, it means that Yoko has cycled 11 km in 20 min.
1 h = 60 min
20 min = 20 ÷ 60 =
13 h
Yoko's cycling speed
= 11 ÷
13 = 11 x
31 = 33 km/h
(b)
Ivory's cycling speed
= 33 + 3
= 36 km/h
Answer(s): (a) 33 km/h ; (b) 36 km/h
