At 06 15, Pamela left Town J and cycled towards Town K. Joelle left Town J and cycled towards Town K at 06 45. Joelle's cycling speed was 2 km/h faster than Pamela. At 12 15, Joelle caught up with Pamela. Find the cycling speed of each cyclist.

1. Pamela
2. Joelle

(a)
Duration that Joelle cycled from 06 45 to 12 15
= 5³⁰₆₀
= 5¹₂ h

Distance that Joelle cycled more than Pamela
= 5¹₂ x 2
= 11 km

However, since Pamela left 30 minutes earlier than Joelle and Joelle caught up with Pamela, it means that Pamela has cycled 11 km in 30 min.

1 h = 60 min 
30 min = 30 ÷ 60 = ¹₂ h

Pamela's cycling speed
= 11 ÷ ¹₂
= 11 x ²₁
= 22 km/h

(b)
Joelle's cycling speed
= 22 + 2
= 24 km/h

Answer(s): (a) 22 km/h ; (b) 24 km/h