At 08 10, Julie left Town P and cycled towards Town Q. Xylia left Town P and cycled towards Town Q at 08 40. Xylia's cycling speed was 6 km/h faster than Julie. At 10 10, Xylia caught up with Julie. Find the cycling speed of each cyclist.
- Julie
- Xylia
(a)
Duration that Xylia cycled from 08 40 to 10 10
= 1
3060 = 1
12 h
Distance that Xylia cycled more than Julie
= 1
12 x 6
= 9 km
However, since Julie left 30 minutes earlier than Xylia and Xylia caught up with Julie, it means that Julie has cycled 9 km in 30 min.
1 h = 60 min
30 min = 30 ÷ 60 =
12 h
Julie's cycling speed
= 9 ÷
12 = 9 x
21 = 18 km/h
(b)
Xylia's cycling speed
= 18 + 6
= 24 km/h
Answer(s): (a) 18 km/h ; (b) 24 km/h
