At 09 25, Wendy left Town W and cycled towards Town X. Shannon left Town W and cycled towards Town X at 09 55. Shannon's cycling speed was 2 km/h faster than Wendy. At 14 25, Shannon caught up with Wendy. Find the cycling speed of each cyclist.

1. Wendy
2. Shannon

(a)
Duration that Shannon cycled from 09 55 to 14 25
= 4³⁰₆₀
= 4¹₂ h

Distance that Shannon cycled more than Wendy
= 4¹₂ x 2
= 9 km

However, since Wendy left 30 minutes earlier than Shannon and Shannon caught up with Wendy, it means that Wendy has cycled 9 km in 30 min.

1 h = 60 min 
30 min = 30 ÷ 60 = ¹₂ h

Wendy's cycling speed
= 9 ÷ ¹₂
= 9 x ²₁
= 18 km/h

(b)
Shannon's cycling speed
= 18 + 2
= 20 km/h

Answer(s): (a) 18 km/h ; (b) 20 km/h