At 08 25, Esther left Town W and cycled towards Town X. Jaslyn left Town W and cycled towards Town X at 08 55. Jaslyn's cycling speed was 2 km/h faster than Esther. At 15 25, Jaslyn caught up with Esther. Find the cycling speed of each cyclist.

1. Esther
2. Jaslyn

(a)
Duration that Jaslyn cycled from 08 55 to 15 25
= 6³⁰₆₀
= 6¹₂ h

Distance that Jaslyn cycled more than Esther
= 6¹₂ x 2
= 13 km

However, since Esther left 30 minutes earlier than Jaslyn and Jaslyn caught up with Esther, it means that Esther has cycled 13 km in 30 min.

1 h = 60 min 
30 min = 30 ÷ 60 = ¹₂ h

Esther's cycling speed
= 13 ÷ ¹₂
= 13 x ²₁
= 26 km/h

(b)
Jaslyn's cycling speed
= 26 + 2
= 28 km/h

Answer(s): (a) 26 km/h ; (b) 28 km/h