At 06 20, Gwen left Town J and cycled towards Town K. Esther left Town J and cycled towards Town K at 06 50. Esther's cycling speed was 2 km/h faster than Gwen. At 12 20, Esther caught up with Gwen. Find the cycling speed of each cyclist.
- Gwen
- Esther
(a)
Duration that Esther cycled from 06 50 to 12 20
= 5
3060 = 5
12 h
Distance that Esther cycled more than Gwen
= 5
12 x 2
= 11 km
However, since Gwen left 30 minutes earlier than Esther and Esther caught up with Gwen, it means that Gwen has cycled 11 km in 30 min.
1 h = 60 min
30 min = 30 ÷ 60 =
12 h
Gwen's cycling speed
= 11 ÷
12 = 11 x
21 = 22 km/h
(b)
Esther's cycling speed
= 22 + 2
= 24 km/h
Answer(s): (a) 22 km/h ; (b) 24 km/h
