At 06 25, Lucy left Town B and cycled towards Town C. Tina left Town B and cycled towards Town C at 06 55. Tina's cycling speed was 4 km/h faster than Lucy. At 11 25, Tina caught up with Lucy. Find the cycling speed of each cyclist.
- Lucy
- Tina
(a)
Duration that Tina cycled from 06 55 to 11 25
= 4
3060 = 4
12 h
Distance that Tina cycled more than Lucy
= 4
12 x 4
= 18 km
However, since Lucy left 30 minutes earlier than Tina and Tina caught up with Lucy, it means that Lucy has cycled 18 km in 30 min.
1 h = 60 min
30 min = 30 ÷ 60 =
12 h
Lucy's cycling speed
= 18 ÷
12 = 18 x
21 = 36 km/h
(b)
Tina's cycling speed
= 36 + 4
= 40 km/h
Answer(s): (a) 36 km/h ; (b) 40 km/h
