At 05 25, Roshel left Town A and cycled towards Town B. Jaslyn left Town A and cycled towards Town B at 05 55. Jaslyn's cycling speed was 4 km/h faster than Roshel. At 10 25, Jaslyn caught up with Roshel. Find the cycling speed of each cyclist.

1. Roshel
2. Jaslyn

(a)
Duration that Jaslyn cycled from 05 55 to 10 25
= 4³⁰₆₀
= 4¹₂ h

Distance that Jaslyn cycled more than Roshel
= 4¹₂ x 4
= 18 km

However, since Roshel left 30 minutes earlier than Jaslyn and Jaslyn caught up with Roshel, it means that Roshel has cycled 18 km in 30 min.

1 h = 60 min 
30 min = 30 ÷ 60 = ¹₂ h

Roshel's cycling speed
= 18 ÷ ¹₂
= 18 x ²₁
= 36 km/h

(b)
Jaslyn's cycling speed
= 36 + 4
= 40 km/h

Answer(s): (a) 36 km/h ; (b) 40 km/h