At 08 25, Jaslyn left Town X and cycled towards Town Y. Erika left Town X and cycled towards Town Y at 08 45. Erika's cycling speed was 3 km/h faster than Jaslyn. At 10 25, Erika caught up with Jaslyn. Find the cycling speed of each cyclist.
- Jaslyn
- Erika
(a)
Duration that Erika cycled from 08 45 to 10 25
= 1
4060 = 1
23 h
Distance that Erika cycled more than Jaslyn
= 1
23 x 3
= 5 km
However, since Jaslyn left 20 minutes earlier than Erika and Erika caught up with Jaslyn, it means that Jaslyn has cycled 5 km in 20 min.
1 h = 60 min
20 min = 20 ÷ 60 =
13 h
Jaslyn's cycling speed
= 5 ÷
13 = 5 x
31 = 15 km/h
(b)
Erika's cycling speed
= 15 + 3
= 18 km/h
Answer(s): (a) 15 km/h ; (b) 18 km/h
