At 09 35, Diana left Town W and cycled towards Town X. Joelle left Town W and cycled towards Town X at 09 55. Joelle's cycling speed was 6 km/h faster than Diana. At 11 35, Joelle caught up with Diana. Find the cycling speed of each cyclist.

1. Diana
2. Joelle

(a)
Duration that Joelle cycled from 09 55 to 11 35
= 1⁴⁰₆₀
= 1²₃ h

Distance that Joelle cycled more than Diana
= 1²₃ x 6
= 10 km

However, since Diana left 20 minutes earlier than Joelle and Joelle caught up with Diana, it means that Diana has cycled 10 km in 20 min.

1 h = 60 min 
20 min = 20 ÷ 60 = ¹₃ h

Diana's cycling speed
= 10 ÷ ¹₃
= 10 x ³₁
= 30 km/h

(b)
Joelle's cycling speed
= 30 + 6
= 36 km/h

Answer(s): (a) 30 km/h ; (b) 36 km/h