At 08 20, Eva left Town B and cycled towards Town C. Roshel left Town B and cycled towards Town C at 08 50. Roshel's cycling speed was 2 km/h faster than Eva. At 10 20, Roshel caught up with Eva. Find the cycling speed of each cyclist.
- Eva
- Roshel
(a)
Duration that Roshel cycled from 08 50 to 10 20
= 1
3060 = 1
12 h
Distance that Roshel cycled more than Eva
= 1
12 x 2
= 3 km
However, since Eva left 30 minutes earlier than Roshel and Roshel caught up with Eva, it means that Eva has cycled 3 km in 30 min.
1 h = 60 min
30 min = 30 ÷ 60 =
12 h
Eva's cycling speed
= 3 ÷
12 = 3 x
21 = 6 km/h
(b)
Roshel's cycling speed
= 6 + 2
= 8 km/h
Answer(s): (a) 6 km/h ; (b) 8 km/h
