At 08 15, Pamela left Town B and cycled towards Town C. Opal left Town B and cycled towards Town C at 08 45. Opal's cycling speed was 2 km/h faster than Pamela. At 15 15, Opal caught up with Pamela. Find the cycling speed of each cyclist.
- Pamela
- Opal
(a)
Duration that Opal cycled from 08 45 to 15 15
= 6
3060 = 6
12 h
Distance that Opal cycled more than Pamela
= 6
12 x 2
= 13 km
However, since Pamela left 30 minutes earlier than Opal and Opal caught up with Pamela, it means that Pamela has cycled 13 km in 30 min.
1 h = 60 min
30 min = 30 ÷ 60 =
12 h
Pamela's cycling speed
= 13 ÷
12 = 13 x
21 = 26 km/h
(b)
Opal's cycling speed
= 26 + 2
= 28 km/h
Answer(s): (a) 26 km/h ; (b) 28 km/h
