At 09 25, Hazel left Town N and cycled towards Town P. Hilda left Town N and cycled towards Town P at 09 55. Hilda's cycling speed was 2 km/h faster than Hazel. At 12 25, Hilda caught up with Hazel. Find the cycling speed of each cyclist.
- Hazel
- Hilda
(a)
Duration that Hilda cycled from 09 55 to 12 25
= 2
3060 = 2
12 h
Distance that Hilda cycled more than Hazel
= 2
12 x 2
= 5 km
However, since Hazel left 30 minutes earlier than Hilda and Hilda caught up with Hazel, it means that Hazel has cycled 5 km in 30 min.
1 h = 60 min
30 min = 30 ÷ 60 =
12 h
Hazel's cycling speed
= 5 ÷
12 = 5 x
21 = 10 km/h
(b)
Hilda's cycling speed
= 10 + 2
= 12 km/h
Answer(s): (a) 10 km/h ; (b) 12 km/h
