At 08 10, Penelope left Town A and cycled towards Town B. Jen left Town A and cycled towards Town B at 08 40. Jen's cycling speed was 2 km/h faster than Penelope. At 11 10, Jen caught up with Penelope. Find the cycling speed of each cyclist.
- Penelope
- Jen
(a)
Duration that Jen cycled from 08 40 to 11 10
= 2
3060 = 2
12 h
Distance that Jen cycled more than Penelope
= 2
12 x 2
= 5 km
However, since Penelope left 30 minutes earlier than Jen and Jen caught up with Penelope, it means that Penelope has cycled 5 km in 30 min.
1 h = 60 min
30 min = 30 ÷ 60 =
12 h
Penelope's cycling speed
= 5 ÷
12 = 5 x
21 = 10 km/h
(b)
Jen's cycling speed
= 10 + 2
= 12 km/h
Answer(s): (a) 10 km/h ; (b) 12 km/h
