At 08 10, Fanny left Town M and cycled towards Town N. Lynn left Town M and cycled towards Town N at 08 40. Lynn's cycling speed was 2 km/h faster than Fanny. At 12 10, Lynn caught up with Fanny. Find the cycling speed of each cyclist.
- Fanny
- Lynn
(a)
Duration that Lynn cycled from 08 40 to 12 10
= 3
3060 = 3
12 h
Distance that Lynn cycled more than Fanny
= 3
12 x 2
= 7 km
However, since Fanny left 30 minutes earlier than Lynn and Lynn caught up with Fanny, it means that Fanny has cycled 7 km in 30 min.
1 h = 60 min
30 min = 30 ÷ 60 =
12 h
Fanny's cycling speed
= 7 ÷
12 = 7 x
21 = 14 km/h
(b)
Lynn's cycling speed
= 14 + 2
= 16 km/h
Answer(s): (a) 14 km/h ; (b) 16 km/h
