At 06 15, Diana left Town R and cycled towards Town S. Kimberly left Town R and cycled towards Town S at 06 45. Kimberly's cycling speed was 2 km/h faster than Diana. At 15 15, Kimberly caught up with Diana. Find the cycling speed of each cyclist.

1. Diana
2. Kimberly

(a)
Duration that Kimberly cycled from 06 45 to 15 15
= 8³⁰₆₀
= 8¹₂ h

Distance that Kimberly cycled more than Diana
= 8¹₂ x 2
= 17 km

However, since Diana left 30 minutes earlier than Kimberly and Kimberly caught up with Diana, it means that Diana has cycled 17 km in 30 min.

1 h = 60 min 
30 min = 30 ÷ 60 = ¹₂ h

Diana's cycling speed
= 17 ÷ ¹₂
= 17 x ²₁
= 34 km/h

(b)
Kimberly's cycling speed
= 34 + 2
= 36 km/h

Answer(s): (a) 34 km/h ; (b) 36 km/h