Albert started driving from Town B towards Town C at 15 30 at an average speed of 60 km/h. Neave began driving from Town B towards Town C at 18 20 at an average speed of 110 km/h.
- At what time did Neave pass Albert on the road?
- 1110 hours after passing Albert, Neave reached Town C. At what time did Albert reach Town C?
(a)
From 15 30 to 18 20 = 2 h 50 min
Time that Albert travelled before Neave started driving = 2 h 50 min
1 h = 60 min
2 h 50 min = 2
5060 h = 2
56 h
Distance that Albert travelled before Neave started driving
= 2
56 x 60
=
176 x 60
= 170 km
Difference between Neave's and Albert's speed
= 110 - 60
= 50 km/h
Time that Neave took to catch up with Albert
= 170 ÷ 50
= 3.4 h
= 3 h 24 min
3 h 24 min after 18 20 = 21 44
Time that Neave passed Albert on the road = 21 44
(b)
1
110 h = 1 h 6 min
Total time that Neave travelled
= 1 h 6 min + 3 h 24 min
= 4 h 30 min
4 h 30 min = 4
3060h = 4
12h
Distance between Town B and Town C
= 4
12 x 110
= 495 km
Time that Albert travelled from Town B to Town C
= 495 ÷ 60
= 8.25 h
= 8 h 15 min
8 h 15 min after 15 30 = 23 45
Time that Albert reached Town C = 23 45
Answer: (a) 21 44; (b) 23 45