Reggie started driving from Town A towards Town B at 14 40 at an average speed of 60 km/h. Vaidev began driving from Town A towards Town B at 16 20 at an average speed of 100 km/h.

1. At what time did Vaidev pass Reggie on the road?
2. 1¹₄ hours after passing Reggie, Vaidev reached Town B. At what time did Reggie reach Town B?

(a)
From 14 40 to 16 20 = 1 h 40 min

Time that Reggie travelled before Vaidev started driving = 1 h 40 min

1 h = 60 min
1 h 40 min = 1⁴⁰₆₀ h = 1²₃ h

Distance that Reggie travelled before Vaidev started driving
= 1²₃ x 60
= ⁵₃ x 60
= 100 km

Difference between Vaidev's and Reggie's speed
= 100 - 60
= 40 km/h

Time that Vaidev took to catch up with Reggie
= 100 ÷ 40
= 2.5 h
= 2 h 30 min

2 h 30 min after 16 20 = 18 50

Time that Vaidev passed Reggie on the road = 18 50

(b)
1¹₄ h = 1 h 15 min

Total time that Vaidev travelled
= 1 h 15 min + 2 h 30 min
= 3 h 45 min

3 h 45 min = 3⁴⁵₆₀h = 3³₄h

Distance between Town A and Town B
= 3³₄ x 100
= 375 km

Time that Reggie travelled from Town A to Town B
= 375 ÷ 60
= 6.25 h
= 6 h 15 min

6 h 15 min after 14 40 = 20 55

Time that Reggie reached Town B = 20 55

Answer: (a) 18 50; (b) 20 55