Pierre started driving from Town W towards Town X at 13 40 at an average speed of 60 km/h. Henry began driving from Town W towards Town X at 15 30 at an average speed of 110 km/h.
- At what time did Henry pass Pierre on the road?
- 1110 hours after passing Pierre, Henry reached Town X. At what time did Pierre reach Town X?
(a)
From 13 40 to 15 30 = 1 h 50 min
Time that Pierre travelled before Henry started driving = 1 h 50 min
1 h = 60 min
1 h 50 min = 1
5060 h = 1
56 h
Distance that Pierre travelled before Henry started driving
= 1
56 x 60
=
116 x 60
= 110 km
Difference between Henry's and Pierre's speed
= 110 - 60
= 50 km/h
Time that Henry took to catch up with Pierre
= 110 ÷ 50
= 2.2 h
= 2 h 12 min
2 h 12 min after 15 30 = 17 42
Time that Henry passed Pierre on the road = 17 42
(b)
1
110 h = 1 h 6 min
Total time that Henry travelled
= 1 h 6 min + 2 h 12 min
= 3 h 18 min
3 h 18 min = 3
1860h = 3
310h
Distance between Town W and Town X
= 3
310 x 110
= 363 km
Time that Pierre travelled from Town W to Town X
= 363 ÷ 60
= 6.05 h
= 6 h 3 min
6 h 3 min after 13 40 = 19 43
Time that Pierre reached Town X = 19 43
Answer: (a) 17 42; (b) 19 43