Nick started driving from City N towards City P at 15 40 at an average speed of 60 km/h. Howard began driving from City N towards City P at 17 20 at an average speed of 100 km/h.
- At what time did Howard pass Nick on the road?
- 114 hours after passing Nick, Howard reached City P. At what time did Nick reach City P?
(a)
From 15 40 to 17 20 = 1 h 40 min
Time that Nick travelled before Howard started driving = 1 h 40 min
1 h = 60 min
1 h 40 min = 1
4060 h = 1
23 h
Distance that Nick travelled before Howard started driving
= 1
23 x 60
=
53 x 60
= 100 km
Difference between Howard's and Nick's speed
= 100 - 60
= 40 km/h
Time that Howard took to catch up with Nick
= 100 ÷ 40
= 2.5 h
= 2 h 30 min
2 h 30 min after 17 20 = 19 50
Time that Howard passed Nick on the road = 19 50
(b)
1
14 h = 1 h 15 min
Total time that Howard travelled
= 1 h 15 min + 2 h 30 min
= 3 h 45 min
3 h 45 min = 3
4560h = 3
34h
Distance between City N and City P
= 3
34 x 100
= 375 km
Time that Nick travelled from City N to City P
= 375 ÷ 60
= 6.25 h
= 6 h 15 min
6 h 15 min after 15 40 = 21 55
Time that Nick reached City P = 21 55
Answer: (a) 19 50; (b) 21 55