David started driving from City T towards City U at 14 30 at an average speed of 60 km/h. Henry began driving from City T towards City U at 16 20 at an average speed of 110 km/h.
- At what time did Henry pass David on the road?
- 1110 hours after passing David, Henry reached City U. At what time did David reach City U?
(a)
From 14 30 to 16 20 = 1 h 50 min
Time that David travelled before Henry started driving = 1 h 50 min
1 h = 60 min
1 h 50 min = 1
5060 h = 1
56 h
Distance that David travelled before Henry started driving
= 1
56 x 60
=
116 x 60
= 110 km
Difference between Henry's and David's speed
= 110 - 60
= 50 km/h
Time that Henry took to catch up with David
= 110 ÷ 50
= 2.2 h
= 2 h 12 min
2 h 12 min after 16 20 = 18 32
Time that Henry passed David on the road = 18 32
(b)
1
110 h = 1 h 6 min
Total time that Henry travelled
= 1 h 6 min + 2 h 12 min
= 3 h 18 min
3 h 18 min = 3
1860h = 3
310h
Distance between City T and City U
= 3
310 x 110
= 363 km
Time that David travelled from City T to City U
= 363 ÷ 60
= 6.05 h
= 6 h 3 min
6 h 3 min after 14 30 = 20 33
Time that David reached City U = 20 33
Answer: (a) 18 32; (b) 20 33