Albert started driving from City U towards City V at 14 30 at an average speed of 60 km/h. Oscar began driving from City U towards City V at 17 20 at an average speed of 110 km/h.
- At what time did Oscar pass Albert on the road?
- 1110 hours after passing Albert, Oscar reached City V. At what time did Albert reach City V?
(a)
From 14 30 to 17 20 = 2 h 50 min
Time that Albert travelled before Oscar started driving = 2 h 50 min
1 h = 60 min
2 h 50 min = 2
5060 h = 2
56 h
Distance that Albert travelled before Oscar started driving
= 2
56 x 60
=
176 x 60
= 170 km
Difference between Oscar's and Albert's speed
= 110 - 60
= 50 km/h
Time that Oscar took to catch up with Albert
= 170 ÷ 50
= 3.4 h
= 3 h 24 min
3 h 24 min after 17 20 = 20 44
Time that Oscar passed Albert on the road = 20 44
(b)
1
110 h = 1 h 6 min
Total time that Oscar travelled
= 1 h 6 min + 3 h 24 min
= 4 h 30 min
4 h 30 min = 4
3060h = 4
12h
Distance between City U and City V
= 4
12 x 110
= 495 km
Time that Albert travelled from City U to City V
= 495 ÷ 60
= 8.25 h
= 8 h 15 min
8 h 15 min after 14 30 = 22 45
Time that Albert reached City V = 22 45
Answer: (a) 20 44; (b) 22 45