Luke started driving from Town P towards Town Q at 13 30 at an average speed of 60 km/h. Ken began driving from Town P towards Town Q at 16 20 at an average speed of 110 km/h.
- At what time did Ken pass Luke on the road?
- 1110 hours after passing Luke, Ken reached Town Q. At what time did Luke reach Town Q?
(a)
From 13 30 to 16 20 = 2 h 50 min
Time that Luke travelled before Ken started driving = 2 h 50 min
1 h = 60 min
2 h 50 min = 2
5060 h = 2
56 h
Distance that Luke travelled before Ken started driving
= 2
56 x 60
=
176 x 60
= 170 km
Difference between Ken's and Luke's speed
= 110 - 60
= 50 km/h
Time that Ken took to catch up with Luke
= 170 ÷ 50
= 3.4 h
= 3 h 24 min
3 h 24 min after 16 20 = 19 44
Time that Ken passed Luke on the road = 19 44
(b)
1
110 h = 1 h 6 min
Total time that Ken travelled
= 1 h 6 min + 3 h 24 min
= 4 h 30 min
4 h 30 min = 4
3060h = 4
12h
Distance between Town P and Town Q
= 4
12 x 110
= 495 km
Time that Luke travelled from Town P to Town Q
= 495 ÷ 60
= 8.25 h
= 8 h 15 min
8 h 15 min after 13 30 = 21 45
Time that Luke reached Town Q = 21 45
Answer: (a) 19 44; (b) 21 45