Owen started driving from City Q towards City R at 13 40 at an average speed of 60 km/h. Lee began driving from City Q towards City R at 15 30 at an average speed of 110 km/h.

1. At what time did Lee pass Owen on the road?
2. 1¹₁₀ hours after passing Owen, Lee reached City R. At what time did Owen reach City R?

(a)
From 13 40 to 15 30 = 1 h 50 min

Time that Owen travelled before Lee started driving = 1 h 50 min

1 h = 60 min
1 h 50 min = 1⁵⁰₆₀ h = 1⁵₆ h

Distance that Owen travelled before Lee started driving
= 1⁵₆ x 60
= ¹¹₆ x 60
= 110 km

Difference between Lee's and Owen's speed
= 110 - 60
= 50 km/h

Time that Lee took to catch up with Owen
= 110 ÷ 50
= 2.2 h
= 2 h 12 min

2 h 12 min after 15 30 = 17 42

Time that Lee passed Owen on the road = 17 42

(b)
1¹₁₀ h = 1 h 6 min

Total time that Lee travelled
= 1 h 6 min + 2 h 12 min
= 3 h 18 min

3 h 18 min = 3¹⁸₆₀h = 3³₁₀h

Distance between City Q and City R
= 3³₁₀ x 110
= 363 km

Time that Owen travelled from City Q to City R
= 363 ÷ 60
= 6.05 h
= 6 h 3 min

6 h 3 min after 13 40 = 19 43

Time that Owen reached City R = 19 43

Answer: (a) 17 42; (b) 19 43