Ryan started driving from City R towards City S at 13 40 at an average speed of 60 km/h. Tommy began driving from City R towards City S at 15 30 at an average speed of 110 km/h.

1. At what time did Tommy pass Ryan on the road?
2. 1¹₁₀ hours after passing Ryan, Tommy reached City S. At what time did Ryan reach City S?

(a)
From 13 40 to 15 30 = 1 h 50 min

Time that Ryan travelled before Tommy started driving = 1 h 50 min

1 h = 60 min
1 h 50 min = 1⁵⁰₆₀ h = 1⁵₆ h

Distance that Ryan travelled before Tommy started driving
= 1⁵₆ x 60
= ¹¹₆ x 60
= 110 km

Difference between Tommy's and Ryan's speed
= 110 - 60
= 50 km/h

Time that Tommy took to catch up with Ryan
= 110 ÷ 50
= 2.2 h
= 2 h 12 min

2 h 12 min after 15 30 = 17 42

Time that Tommy passed Ryan on the road = 17 42

(b)
1¹₁₀ h = 1 h 6 min

Total time that Tommy travelled
= 1 h 6 min + 2 h 12 min
= 3 h 18 min

3 h 18 min = 3¹⁸₆₀h = 3³₁₀h

Distance between City R and City S
= 3³₁₀ x 110
= 363 km

Time that Ryan travelled from City R to City S
= 363 ÷ 60
= 6.05 h
= 6 h 3 min

6 h 3 min after 13 40 = 19 43

Time that Ryan reached City S = 19 43

Answer: (a) 17 42; (b) 19 43