Riordan started driving from Town A towards Town B at 14 40 at an average speed of 60 km/h. Seth began driving from Town A towards Town B at 17 30 at an average speed of 110 km/h.
- At what time did Seth pass Riordan on the road?
- 1110 hours after passing Riordan, Seth reached Town B. At what time did Riordan reach Town B?
(a)
From 14 40 to 17 30 = 2 h 50 min
Time that Riordan travelled before Seth started driving = 2 h 50 min
1 h = 60 min
2 h 50 min = 2
5060 h = 2
56 h
Distance that Riordan travelled before Seth started driving
= 2
56 x 60
=
176 x 60
= 170 km
Difference between Seth's and Riordan's speed
= 110 - 60
= 50 km/h
Time that Seth took to catch up with Riordan
= 170 ÷ 50
= 3.4 h
= 3 h 24 min
3 h 24 min after 17 30 = 20 54
Time that Seth passed Riordan on the road = 20 54
(b)
1
110 h = 1 h 6 min
Total time that Seth travelled
= 1 h 6 min + 3 h 24 min
= 4 h 30 min
4 h 30 min = 4
3060h = 4
12h
Distance between Town A and Town B
= 4
12 x 110
= 495 km
Time that Riordan travelled from Town A to Town B
= 495 ÷ 60
= 8.25 h
= 8 h 15 min
8 h 15 min after 14 40 = 22 55
Time that Riordan reached Town B = 22 55
Answer: (a) 20 54; (b) 22 55