Daniel started driving from City A towards City B at 14 45 at an average speed of 60 km/h. Fabian began driving from City A towards City B at 16 35 at an average speed of 110 km/h.
- At what time did Fabian pass Daniel on the road?
- 1110 hours after passing Daniel, Fabian reached City B. At what time did Daniel reach City B?
(a)
From 14 45 to 16 35 = 1 h 50 min
Time that Daniel travelled before Fabian started driving = 1 h 50 min
1 h = 60 min
1 h 50 min = 1
5060 h = 1
56 h
Distance that Daniel travelled before Fabian started driving
= 1
56 x 60
=
116 x 60
= 110 km
Difference between Fabian's and Daniel's speed
= 110 - 60
= 50 km/h
Time that Fabian took to catch up with Daniel
= 110 ÷ 50
= 2.2 h
= 2 h 12 min
2 h 12 min after 16 35 = 18 47
Time that Fabian passed Daniel on the road = 18 47
(b)
1
110 h = 1 h 6 min
Total time that Fabian travelled
= 1 h 6 min + 2 h 12 min
= 3 h 18 min
3 h 18 min = 3
1860h = 3
310h
Distance between City A and City B
= 3
310 x 110
= 363 km
Time that Daniel travelled from City A to City B
= 363 ÷ 60
= 6.05 h
= 6 h 3 min
6 h 3 min after 14 45 = 20 48
Time that Daniel reached City B = 20 48
Answer: (a) 18 47; (b) 20 48