Michael started driving from City H towards City J at 13 30 at an average speed of 60 km/h. Seth began driving from City H towards City J at 15 10 at an average speed of 100 km/h.

1. At what time did Seth pass Michael on the road?
2. 1¹₄ hours after passing Michael, Seth reached City J. At what time did Michael reach City J?

(a)
From 13 30 to 15 10 = 1 h 40 min

Time that Michael travelled before Seth started driving = 1 h 40 min

1 h = 60 min
1 h 40 min = 1⁴⁰₆₀ h = 1²₃ h

Distance that Michael travelled before Seth started driving
= 1²₃ x 60
= ⁵₃ x 60
= 100 km

Difference between Seth's and Michael's speed
= 100 - 60
= 40 km/h

Time that Seth took to catch up with Michael
= 100 ÷ 40
= 2.5 h
= 2 h 30 min

2 h 30 min after 15 10 = 17 40

Time that Seth passed Michael on the road = 17 40

(b)
1¹₄ h = 1 h 15 min

Total time that Seth travelled
= 1 h 15 min + 2 h 30 min
= 3 h 45 min

3 h 45 min = 3⁴⁵₆₀h = 3³₄h

Distance between City H and City J
= 3³₄ x 100
= 375 km

Time that Michael travelled from City H to City J
= 375 ÷ 60
= 6.25 h
= 6 h 15 min

6 h 15 min after 13 30 = 19 45

Time that Michael reached City J = 19 45

Answer: (a) 17 40; (b) 19 45