Wesley started driving from City E towards City F at 13 40 at an average speed of 60 km/h. Peter began driving from City E towards City F at 16 30 at an average speed of 110 km/h.
- At what time did Peter pass Wesley on the road?
- 1110 hours after passing Wesley, Peter reached City F. At what time did Wesley reach City F?
(a)
From 13 40 to 16 30 = 2 h 50 min
Time that Wesley travelled before Peter started driving = 2 h 50 min
1 h = 60 min
2 h 50 min = 2
5060 h = 2
56 h
Distance that Wesley travelled before Peter started driving
= 2
56 x 60
=
176 x 60
= 170 km
Difference between Peter's and Wesley's speed
= 110 - 60
= 50 km/h
Time that Peter took to catch up with Wesley
= 170 ÷ 50
= 3.4 h
= 3 h 24 min
3 h 24 min after 16 30 = 19 54
Time that Peter passed Wesley on the road = 19 54
(b)
1
110 h = 1 h 6 min
Total time that Peter travelled
= 1 h 6 min + 3 h 24 min
= 4 h 30 min
4 h 30 min = 4
3060h = 4
12h
Distance between City E and City F
= 4
12 x 110
= 495 km
Time that Wesley travelled from City E to City F
= 495 ÷ 60
= 8.25 h
= 8 h 15 min
8 h 15 min after 13 40 = 21 55
Time that Wesley reached City F = 21 55
Answer: (a) 19 54; (b) 21 55