Lee started driving from Town B towards Town C at 13 45 at an average speed of 60 km/h. Owen began driving from Town B towards Town C at 15 35 at an average speed of 110 km/h.

1. At what time did Owen pass Lee on the road?
2. 1¹₁₀ hours after passing Lee, Owen reached Town C. At what time did Lee reach Town C?

(a)
From 13 45 to 15 35 = 1 h 50 min

Time that Lee travelled before Owen started driving = 1 h 50 min

1 h = 60 min
1 h 50 min = 1⁵⁰₆₀ h = 1⁵₆ h

Distance that Lee travelled before Owen started driving
= 1⁵₆ x 60
= ¹¹₆ x 60
= 110 km

Difference between Owen's and Lee's speed
= 110 - 60
= 50 km/h

Time that Owen took to catch up with Lee
= 110 ÷ 50
= 2.2 h
= 2 h 12 min

2 h 12 min after 15 35 = 17 47

Time that Owen passed Lee on the road = 17 47

(b)
1¹₁₀ h = 1 h 6 min

Total time that Owen travelled
= 1 h 6 min + 2 h 12 min
= 3 h 18 min

3 h 18 min = 3¹⁸₆₀h = 3³₁₀h

Distance between Town B and Town C
= 3³₁₀ x 110
= 363 km

Time that Lee travelled from Town B to Town C
= 363 ÷ 60
= 6.05 h
= 6 h 3 min

6 h 3 min after 13 45 = 19 48

Time that Lee reached Town C = 19 48

Answer: (a) 17 47; (b) 19 48