Cody started driving from City B towards City C at 15 30 at an average speed of 60 km/h. Seth began driving from City B towards City C at 17 10 at an average speed of 100 km/h.

1. At what time did Seth pass Cody on the road?
2. 1¹₄ hours after passing Cody, Seth reached City C. At what time did Cody reach City C?

(a)
From 15 30 to 17 10 = 1 h 40 min

Time that Cody travelled before Seth started driving = 1 h 40 min

1 h = 60 min
1 h 40 min = 1⁴⁰₆₀ h = 1²₃ h

Distance that Cody travelled before Seth started driving
= 1²₃ x 60
= ⁵₃ x 60
= 100 km

Difference between Seth's and Cody's speed
= 100 - 60
= 40 km/h

Time that Seth took to catch up with Cody
= 100 ÷ 40
= 2.5 h
= 2 h 30 min

2 h 30 min after 17 10 = 19 40

Time that Seth passed Cody on the road = 19 40

(b)
1¹₄ h = 1 h 15 min

Total time that Seth travelled
= 1 h 15 min + 2 h 30 min
= 3 h 45 min

3 h 45 min = 3⁴⁵₆₀h = 3³₄h

Distance between City B and City C
= 3³₄ x 100
= 375 km

Time that Cody travelled from City B to City C
= 375 ÷ 60
= 6.25 h
= 6 h 15 min

6 h 15 min after 15 30 = 21 45

Time that Cody reached City C = 21 45

Answer: (a) 19 40; (b) 21 45