Luis started driving from City F towards City G at 15 30 at an average speed of 60 km/h. Peter began driving from City F towards City G at 18 20 at an average speed of 110 km/h.

1. At what time did Peter pass Luis on the road?
2. 1¹₁₀ hours after passing Luis, Peter reached City G. At what time did Luis reach City G?

(a)
From 15 30 to 18 20 = 2 h 50 min

Time that Luis travelled before Peter started driving = 2 h 50 min

1 h = 60 min
2 h 50 min = 2⁵⁰₆₀ h = 2⁵₆ h

Distance that Luis travelled before Peter started driving
= 2⁵₆ x 60
= ¹⁷₆ x 60
= 170 km

Difference between Peter's and Luis's speed
= 110 - 60
= 50 km/h

Time that Peter took to catch up with Luis
= 170 ÷ 50
= 3.4 h
= 3 h 24 min

3 h 24 min after 18 20 = 21 44

Time that Peter passed Luis on the road = 21 44

(b)
1¹₁₀ h = 1 h 6 min

Total time that Peter travelled
= 1 h 6 min + 3 h 24 min
= 4 h 30 min

4 h 30 min = 4³⁰₆₀h = 4¹₂h

Distance between City F and City G
= 4¹₂ x 110
= 495 km

Time that Luis travelled from City F to City G
= 495 ÷ 60
= 8.25 h
= 8 h 15 min

8 h 15 min after 15 30 = 23 45

Time that Luis reached City G = 23 45

Answer: (a) 21 44; (b) 23 45