Michael started driving from Town G towards Town H at 15 30 at an average speed of 60 km/h. Perry began driving from Town G towards Town H at 18 20 at an average speed of 110 km/h.

1. At what time did Perry pass Michael on the road?
2. 1¹₁₀ hours after passing Michael, Perry reached Town H. At what time did Michael reach Town H?

(a)
From 15 30 to 18 20 = 2 h 50 min

Time that Michael travelled before Perry started driving = 2 h 50 min

1 h = 60 min
2 h 50 min = 2⁵⁰₆₀ h = 2⁵₆ h

Distance that Michael travelled before Perry started driving
= 2⁵₆ x 60
= ¹⁷₆ x 60
= 170 km

Difference between Perry's and Michael's speed
= 110 - 60
= 50 km/h

Time that Perry took to catch up with Michael
= 170 ÷ 50
= 3.4 h
= 3 h 24 min

3 h 24 min after 18 20 = 21 44

Time that Perry passed Michael on the road = 21 44

(b)
1¹₁₀ h = 1 h 6 min

Total time that Perry travelled
= 1 h 6 min + 3 h 24 min
= 4 h 30 min

4 h 30 min = 4³⁰₆₀h = 4¹₂h

Distance between Town G and Town H
= 4¹₂ x 110
= 495 km

Time that Michael travelled from Town G to Town H
= 495 ÷ 60
= 8.25 h
= 8 h 15 min

8 h 15 min after 15 30 = 23 45

Time that Michael reached Town H = 23 45

Answer: (a) 21 44; (b) 23 45