Jack left City Y for City X at 07 49. Gillian left City Y for City C at the same time. At 11 49, they were 640 km apart. Both maintained a constant speed and reached their destination at the same time at 14 25.
- Find the distance between Cities A and C.
- If Gillian was 35 the speed of Jack, find Jack's speed.
(a)
Time taken for Jack and Gillian to travel 07 49 to 11 49 = 4 h
Time taken for Jack and Gillian to travel 07 49 to 14 25 = 6 h 36 min = 6
3660 h = 6
35 h
Distance travelled by Jack and Gillian in 1 hour
= 640 ÷ 4
= 160 km
Total distance
= 6
35 x 160
= 1056 km
(b)
Gillian's distance : Jack's distance
3 : 5
Gillian's speed : Jack's speed
3 : 5
8 u = 160 km
1 u = 160 ÷ 8 = 20 km
Jack's speed
= 5 u
= 5 x 20
= 100 km/h
Answer(s): (a) 1056 km; (b) 100km/h