Howard left City U for City T at 05 29. Dana left City U for City C at the same time. At 10 29, they were 900 km apart. Both maintained a constant speed and reached their destination at the same time at 12 27.
- Find the distance between Cities A and C.
- If Dana was 57 the speed of Howard, find Howard's speed.
(a)
Time taken for Howard and Dana to travel 05 29 to 10 29 = 5 h
Time taken for Howard and Dana to travel 05 29 to 12 27 = 6 h 58 min = 6
5860 h = 6
2930 h
Distance travelled by Howard and Dana in 1 hour
= 900 ÷ 5
= 180 km
Total distance
= 6
2930 x 180
= 1254 km
(b)
Dana's distance : Howard's distance
5 : 7
Dana's speed : Howard's speed
5 : 7
12 u = 180 km
1 u = 180 ÷ 12 = 15 km
Howard's speed
= 7 u
= 7 x 15
= 105 km/h
Answer(s): (a) 1254 km; (b) 105km/h