Seth left City Y for City X at 07 49. Cathy left City Y for City C at the same time. At 11 49, they were 576 km apart. Both maintained a constant speed and reached their destination at the same time at 14 29.
- Find the distance between Cities A and C.
- If Cathy was 57 the speed of Seth, find Seth's speed.
(a)
Time taken for Seth and Cathy to travel 07 49 to 11 49 = 4 h
Time taken for Seth and Cathy to travel 07 49 to 14 29 = 6 h 40 min = 6
4060 h = 6
23 h
Distance travelled by Seth and Cathy in 1 hour
= 576 ÷ 4
= 144 km
Total distance
= 6
23 x 144
= 960 km
(b)
Cathy's distance : Seth's distance
5 : 7
Cathy's speed : Seth's speed
5 : 7
12 u = 144 km
1 u = 144 ÷ 12 = 12 km
Seth's speed
= 7 u
= 7 x 12
= 84 km/h
Answer(s): (a) 960 km; (b) 84km/h