Peter left City A for City Z at 09 25. Ivory left City A for City C at the same time. At 11 25, they were 280 km apart. Both maintained a constant speed and reached their destination at the same time at 13 13.
- Find the distance between Cities A and C.
- If Ivory was 59 the speed of Peter, find Peter's speed.
(a)
Time taken for Peter and Ivory to travel 09 25 to 11 25 = 2 h
Time taken for Peter and Ivory to travel 09 25 to 13 13 = 3 h 48 min = 3
4860 h = 3
45 h
Distance travelled by Peter and Ivory in 1 hour
= 280 ÷ 2
= 140 km
Total distance
= 3
45 x 140
= 532 km
(b)
Ivory's distance : Peter's distance
5 : 9
Ivory's speed : Peter's speed
5 : 9
14 u = 140 km
1 u = 140 ÷ 14 = 10 km
Peter's speed
= 9 u
= 9 x 10
= 90 km/h
Answer(s): (a) 532 km; (b) 90km/h