Nick left City G for City F at 09 29. Fanny left City G for City C at the same time. At 11 29, they were 408 km apart. Both maintained a constant speed and reached their destination at the same time at 15 24.
- Find the distance between Cities A and C.
- If Fanny was 89 the speed of Nick, find Nick's speed.
(a)
Time taken for Nick and Fanny to travel 09 29 to 11 29 = 2 h
Time taken for Nick and Fanny to travel 09 29 to 15 24 = 5 h 55 min = 5
5560 h = 5
1112 h
Distance travelled by Nick and Fanny in 1 hour
= 408 ÷ 2
= 204 km
Total distance
= 5
1112 x 204
= 1207 km
(b)
Fanny's distance : Nick's distance
8 : 9
Fanny's speed : Nick's speed
8 : 9
17 u = 204 km
1 u = 204 ÷ 17 = 12 km
Nick's speed
= 9 u
= 9 x 12
= 108 km/h
Answer(s): (a) 1207 km; (b) 108km/h