Justin left City X for City W at 07 35. Eva left City X for City C at the same time. At 11 35, they were 760 km apart. Both maintained a constant speed and reached their destination at the same time at 13 23.
- Find the distance between Cities A and C.
- If Eva was 910 the speed of Justin, find Justin's speed.
(a)
Time taken for Justin and Eva to travel 07 35 to 11 35 = 4 h
Time taken for Justin and Eva to travel 07 35 to 13 23 = 5 h 48 min = 5
4860 h = 5
45 h
Distance travelled by Justin and Eva in 1 hour
= 760 ÷ 4
= 190 km
Total distance
= 5
45 x 190
= 1102 km
(b)
Eva's distance : Justin's distance
9 : 10
Eva's speed : Justin's speed
9 : 10
19 u = 190 km
1 u = 190 ÷ 19 = 10 km
Justin's speed
= 10 u
= 10 x 10
= 100 km/h
Answer(s): (a) 1102 km; (b) 100km/h