Jeremy left City C for City B at 08 49. Diana left City C for City C at the same time. At 10 49, they were 408 km apart. Both maintained a constant speed and reached their destination at the same time at 14 29.
- Find the distance between Cities A and C.
- If Diana was 89 the speed of Jeremy, find Jeremy's speed.
(a)
Time taken for Jeremy and Diana to travel 08 49 to 10 49 = 2 h
Time taken for Jeremy and Diana to travel 08 49 to 14 29 = 5 h 40 min = 5
4060 h = 5
23 h
Distance travelled by Jeremy and Diana in 1 hour
= 408 ÷ 2
= 204 km
Total distance
= 5
23 x 204
= 1156 km
(b)
Diana's distance : Jeremy's distance
8 : 9
Diana's speed : Jeremy's speed
8 : 9
17 u = 204 km
1 u = 204 ÷ 17 = 12 km
Jeremy's speed
= 9 u
= 9 x 12
= 108 km/h
Answer(s): (a) 1156 km; (b) 108km/h