Jack left City B for City A at 08 23. Sarah left City B for City C at the same time. At 11 23, they were 594 km apart. Both maintained a constant speed and reached their destination at the same time at 14 13.
- Find the distance between Cities A and C.
- If Sarah was 45 the speed of Jack, find Jack's speed.
(a)
Time taken for Jack and Sarah to travel 08 23 to 11 23 = 3 h
Time taken for Jack and Sarah to travel 08 23 to 14 13 = 5 h 50 min = 5
5060 h = 5
56 h
Distance travelled by Jack and Sarah in 1 hour
= 594 ÷ 3
= 198 km
Total distance
= 5
56 x 198
= 1155 km
(b)
Sarah's distance : Jack's distance
4 : 5
Sarah's speed : Jack's speed
4 : 5
9 u = 198 km
1 u = 198 ÷ 9 = 22 km
Jack's speed
= 5 u
= 5 x 22
= 110 km/h
Answer(s): (a) 1155 km; (b) 110km/h