Peter left City Y for City X at 09 25. Vanessa left City Y for City C at the same time. At 11 25, they were 264 km apart. Both maintained a constant speed and reached their destination at the same time at 13 20.
- Find the distance between Cities A and C.
- If Vanessa was 47 the speed of Peter, find Peter's speed.
(a)
Time taken for Peter and Vanessa to travel 09 25 to 11 25 = 2 h
Time taken for Peter and Vanessa to travel 09 25 to 13 20 = 3 h 55 min = 3
5560 h = 3
1112 h
Distance travelled by Peter and Vanessa in 1 hour
= 264 ÷ 2
= 132 km
Total distance
= 3
1112 x 132
= 517 km
(b)
Vanessa's distance : Peter's distance
4 : 7
Vanessa's speed : Peter's speed
4 : 7
11 u = 132 km
1 u = 132 ÷ 11 = 12 km
Peter's speed
= 7 u
= 7 x 12
= 84 km/h
Answer(s): (a) 517 km; (b) 84km/h