Vincent left City T for City S at 09 43. Wendy left City T for City C at the same time. At 13 43, they were 840 km apart. Both maintained a constant speed and reached their destination at the same time at 15 21.

1. Find the distance between Cities A and C.
2. If Wendy was ⁷₈ the speed of Vincent, find Vincent's speed.

(a)
Time taken for Vincent and Wendy to travel 09 43 to 13 43 = 4 h
Time taken for Vincent and Wendy to travel 09 43 to 15 21 = 5 h 38 min = 5³⁸₆₀ h = 5¹⁹₃₀ h

Distance travelled by Vincent and Wendy in 1 hour
= 840 ÷ 4
= 210 km

Total distance
= 5¹⁹₃₀ x 210
= 1183 km

(b)
Wendy's distance : Vincent's distance
7 : 8

Wendy's speed : Vincent's speed
7 : 8

15 u = 210 km
1 u = 210 ÷ 15 = 14 km

Vincent's speed
= 8 u
= 8 x 14
= 112 km/h

Answer(s): (a) 1183 km; (b) 112km/h