Will left City L for City K at 08 32. Wendy left City L for City C at the same time. At 12 32, they were 660 km apart. Both maintained a constant speed and reached their destination at the same time at 15 28.
- Find the distance between Cities A and C.
- If Wendy was 78 the speed of Will, find Will's speed.
(a)
Time taken for Will and Wendy to travel 08 32 to 12 32 = 4 h
Time taken for Will and Wendy to travel 08 32 to 15 28 = 6 h 56 min = 6
5660 h = 6
1415 h
Distance travelled by Will and Wendy in 1 hour
= 660 ÷ 4
= 165 km
Total distance
= 6
1415 x 165
= 1144 km
(b)
Wendy's distance : Will's distance
7 : 8
Wendy's speed : Will's speed
7 : 8
15 u = 165 km
1 u = 165 ÷ 15 = 11 km
Will's speed
= 8 u
= 8 x 11
= 88 km/h
Answer(s): (a) 1144 km; (b) 88km/h