Xavier left City J for City H at 07 41. Jane left City J for City C at the same time. At 12 41, they were 825 km apart. Both maintained a constant speed and reached their destination at the same time at 14 33.
- Find the distance between Cities A and C.
- If Jane was 78 the speed of Xavier, find Xavier's speed.
(a)
Time taken for Xavier and Jane to travel 07 41 to 12 41 = 5 h
Time taken for Xavier and Jane to travel 07 41 to 14 33 = 6 h 52 min = 6
5260 h = 6
1315 h
Distance travelled by Xavier and Jane in 1 hour
= 825 ÷ 5
= 165 km
Total distance
= 6
1315 x 165
= 1133 km
(b)
Jane's distance : Xavier's distance
7 : 8
Jane's speed : Xavier's speed
7 : 8
15 u = 165 km
1 u = 165 ÷ 15 = 11 km
Xavier's speed
= 8 u
= 8 x 11
= 88 km/h
Answer(s): (a) 1133 km; (b) 88km/h