Ethan left City W for City V at 06 30. Vanessa left City W for City C at the same time. At 11 30, they were 975 km apart. Both maintained a constant speed and reached their destination at the same time at 13 26.
- Find the distance between Cities A and C.
- If Vanessa was 78 the speed of Ethan, find Ethan's speed.
(a)
Time taken for Ethan and Vanessa to travel 06 30 to 11 30 = 5 h
Time taken for Ethan and Vanessa to travel 06 30 to 13 26 = 6 h 56 min = 6
5660 h = 6
1415 h
Distance travelled by Ethan and Vanessa in 1 hour
= 975 ÷ 5
= 195 km
Total distance
= 6
1415 x 195
= 1352 km
(b)
Vanessa's distance : Ethan's distance
7 : 8
Vanessa's speed : Ethan's speed
7 : 8
15 u = 195 km
1 u = 195 ÷ 15 = 13 km
Ethan's speed
= 8 u
= 8 x 13
= 104 km/h
Answer(s): (a) 1352 km; (b) 104km/h